Efficiently calculating integer powers of float

 static float pow(float base, int exp) {
  float result = 1;
  if(exp<0) return 1.0f/pow(base,-exp);
  while (exp!=0) {
   if ((exp & 1)!=0) result *= base;
   exp >>= 1;
   base *= base;
  }
  return result;
 }